Find The 9th Term Of The Arithmetic Sequence With A\Xb9 = 10 And D = \Xbd

Find the 9th term of the arithmetic sequence with a¹ = 10 and d = ½

 

Answer:The 9th term is 108

Step-by-step explanation:

Sn= n/2(a1+n-1)d)

S9=9/2(2(10)+(9-1)1/2

S9=9/2(20+4)

S9=4.5(24)

S9=108


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